Make sure you learn the definition for a photon: discrete quantity / packet / quantum of electromagnetic energy are all acceptable definitions
E = hf

Light of wavelength 490 nm is incident normally on a surface, as shown in the diagram.

The power of the light is 3.6 mW. The light is completely absorbed by the surface.Calculate the number of photons incident on the surface in 2.0 s.
Step 1: Write down the known quantities
Wavelength, λ = 490 nm = 490 × 10-9 m
Power, P = 3.6 mW = 3.6 × 10-3 W
Time, t = 2.0 s
Step 2: Write the equations for wave speed and photon energy


Step 3: Calculate the energy of one photon

Step 4: Calculate the number of photons hitting the surface every second

Step 5: Calculate the number of photons that hit the surface in 2 s
(8.9 × 1015) × 2 = 1.8 × 1016
The values of Planck’s constant and the speed of light will always be given to you in an exam, however, it helps to memorise them to speed up calculation questions!

A 5.0 mW laser beam is incident normally on a fixed metal plate. The cross-sectional area of the beam is 8.0 × 10-6 m2. The light from the laser has frequency 5.6 × 1014 Hz.Assuming that all the photons are absorbed by the plate, calculate the momentum of the photon, and the pressure exerted by the laser beam on the metal plate.
Step 1: Write down the known quantities
Power, P = 5.0 mW = 5.0 × 10-3 W
Frequency, f = 5.6 × 1014 Hz
Cross-sectional area, A = 8.0 × 10-6 m2
Step 2: Write the equations for photon energy and momentum
photon energy: E = hf

Step 3: Calculate the photon momentum

Step 4: Calculate the number of photons incident on the plate every second

Step 5: Calculate the force exerted on the plate in a 1.0 s time interval
Force = rate of change of momentum
= number of photons per second × momentum of each photon
= (1.35 × 1016) × (1.24 × 10-27)
= 1.67 × 10-11 N
Step 6: Calculate the pressure

转载自savemyexams
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