
Work is done on a positive test charge Q to move it from the negatively charged plate A to the positively charged plate B. This means its electric potential energy increases
The electric field strength is proportional to the gradient of the electric potential
The electric field at a particular point is equal to the gradient of a potential-distance graph at that point
The rate of change of electric potential with respect to displacement in the direction of the field

The electric potential around a positive charge decreases with distance and increases with distance around a negative charge
An electric field is set up between two pairs of oppositely charged plates, set X and set Y.
A graph showing how the electric potential V varies with distance d is shown for both set X and set Y.

State and explain which set creates the largest electric field strength.
Step 1: Recall the relationship between electric field strength and electric potential
Step 2: Interpret the gradient of the potential-distance graph

Step 3: State and explain the conclusion
Remember that whether the electric potential increases or decreases depends on the charge that is producing the potential!
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