The work function + the maximum kinetic energy of the photoelectron
E = hf = Φ + ½ mv2max
The minimum energy required to release a photoelectron from the surface of a metal



In the photoelectric effect, a single photon may cause a surface electron to be released if it has sufficient energy
y = mx + c
KEmax = hf - Φ

The minimum frequency of incident electromagnetic radiation required to remove a photoelectron from the surface of a metal
The graph below shows how the maximum kinetic energy Ek of electrons emitted from the surface of sodium metal varies with the frequency f of the incident radiation.
Calculate the work function of sodium in eV.
Step 1: Write out the photoelectric equation and rearrange to fit the equation of a straight line
E = hf = Φ + ½ mv2max → KEmax = hf - Φ
y = mx + c
Step 2: Identify the threshold frequency from the x-axis of the graph
When Ek = 0, f = f0
Therefore, the threshold frequency is f0 = 4 × 1014 Hz
Step 3: Calculate the work function
From the graph at f0, ½ mvmax2 = 0
Φ = hf0 = (6.63 × 10-34) × (4 × 1014) = 2.652 × 10-19 J
Step 4: Convert the work function into eV
1 eV = 1.6 × 10-19 J J → eV: divide by 1.6 × 10-19

When using the photoelectric effect equation, hf, Φ and KEmax must all have the same units, and that the S.I. unit of energy is Joules.
But the energy involved in these interactions is tiny, which is why we use a different unit for it, the electron volt. Make sure to convert any values given in eV into Joules before starting to calculate.
Remember that the eV is much smaller than the Joule, so your value of eV will be high in comparison. This is why we often use MeV when describing these energies.
转载自savemyexams
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