
Refraction of light through a glass block

n1 sin θ1 = n2 sin θ2

Snell's Law is used to find the refractive indices or the angles to the normal at a boundary
A light ray is directed at a vertical face of a glass cube. The angle of incidence at the vertical face is 39° and the angle of refraction is 25° as shown in the diagram.
Show that the refractive index of the glass is about 1.5.


Always double-check if your calculations for the refractive index are greater than 1. Otherwise, something has definitely gone wrong in your calculation!
The refractive index of air will not be given in the question. Always assume that nair = 1.
Always check that the angle of incidence and refraction are the angles between the normal and the light ray. Remember the normal line is not really there - it has been drawn in to give you a place to measure from.
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