CIE A Level Chemistry复习笔记6.3.6 Stability Constants, Kstab
Define & Write a Stability Constant for a Complex
- When transition element ions are in aqueous solutions, they will automatically become hydrated
- Water molecules will surround the ion and act as ligands by forming dative covalent bonds to the central metal ion
- When there are other potential ligands present in solution, there is a competing equilibrium in ligand exchange and the most stable complex will be formed
- For example, a Co(II) ion in solution will form a [Co(H2O)6]2+ complex
- Adding ammonia results in the stepwise substitution of the water ligands by ammonia ligands until a stable complex of [Co(NH3)4(H2O)2]2+ is formed
[Cu(H2O)6]2+ + 4NH3 ⇌ [Cu(NH3)4(H2O)2]2+ + 4H2O
- For the substitution reaction above, there are four stepwise constants:
[Co(H2O)6]2+ + NH3 ⇌ [Co(NH3)(H2O)5]2+ + H2O K1
[Co(NH3)(H2O)5]2+ + NH3 ⇌ [Co(NH3)2(H2O)4]2+ + H2O K2
[Co(NH3)2(H2O)4]2+ + NH3 ⇌ [Co(NH3)3(H2O)3]2+ + H2O K3
[Co(NH3)3(H2O)3]2+ + NH3 ⇌ [Co(NH3)4(H2O)2]2+ + H2O K4
- These stepwise constants are summarised in the overall stability constant, Kstab
- The stability constant is the equilibrium constant for the formation of the complex ion in a solvent from its constituent ions or molecules
Expression of Kstab
- The expression for Kstab can be deduced in a similar way as the expression for the equilibrium constant (Kc)
- For example, the equilibrium expression for the substitution of water ligands by ammonia ligands in the Co(II) complex is:
[Co(H2O)6]2+ + 4NH3 ⇌ [Co(NH3)4(H2O)2]2+ + 4H2O
- The concentration of water is not included in the expression as the water is in excess
- Therefore, any water produced in the reaction is negligible compared to the water that is already present
- The units of the Kstab can be deduced from the expression in a similar way to the units of Kc
- The stability constants can be used to compare the stability of ligands relative to the aqueous metal ion where the ligand is water
- The larger the Kstab value, the more stable the complex formed is
Calculations Involving Stability Constants
- If the concentrations of the transition element complex and the reacting ligands are known, the expression for the stability constant (Kstab) can be used to determine which complex is more stable
- The greater the value of Kstab the more stable the complex is
转载自savemyexams
以上就是关于【CIE A Level Chemistry复习笔记6.3.6 Stability Constants, Kstab】的解答，如需了解学校/赛事/课程动态，可至翰林教育官网获取更多信息。
往期文章阅读推荐：
翰林独家 | 经济学竞赛核心精讲，一册打通NEC/IEO/USAEBO！
2026 ALEVEL 夏考A率出炉！爱德思vs牛津AQA，哪些科目真的“好出分”？
翰林AMC8视频课重磅上线！
国际竞赛真题资源免费领取
