Br2(l) + 2e- ⇌ 2Br-(aq) voltage = +1.09 V
Na+(aq) + e- ⇌ Na(s) voltage = -2.71 V
Br2(l) + 2e- ⇌ 2Br-(aq) Eꝋ = +1.09 V
2H+(aq) + 2e- ⇌ H2(g) Eꝋ = 0.00 V
Na+ (aq) + e- ⇌ Na(s) Eꝋ = -2.71 V
2H+ (aq) + 2e- ⇌ H2(g) Eꝋ = 0.00 V
Ecellꝋ = (+1.09) - (-2.71)
= +3.80 V
Cu(s) → Cu2+(aq) + 2e-

Oxidation of copper ions
Cu2+(aq) + 2e- → Cu(s)

Reduction of copper ions
Cu2+ (aq) + 2e- ⇌ Cu (s)
V2+ (aq) + 2e- ⇌ V(s)
2H+ (aq) + 2e- ⇌ H2 (g)

The standard electrode potential of a half-cell can be determined by connecting it to a standard hydrogen electrode
转载自savemyexams
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