The magnitude of the induced e.m.f is directly proportional to the rate of change of magnetic flux linkage
Problems Involving Faraday’s Law
This equation shows:
A small rectangular coil contains 350 turns of wire. The longer sides are 3.5 cm and the shorter sides are 1.4 cm.

The coil is held between the poles of a large magnet so that the coil can rotate about an axis through its centre. The magnet produces a uniform magnetic field of flux density 80 mT between its poles. The coil is positioned horizontally and then turned through an angle of 40° in a time of 0.18 s.
Calculate the magnitude of the average e.m.f induced in the coil.
Step 1: Write down the known quantities
Step 2: Write out the equation for Faraday’s law:
Step 3: Write out the equation for the change in flux linkage:
Δ(NΦ) = NA(ΔB)
Step 4: Determine the change in magnetic flux linkage
Δ(NΦ) = NA(ΔB) = 350 × (4.9 × 10-4) × (80 × 10-3) = 0.014 Wb turns
Step 5: Substitute change in flux linkage and time into Faraday’s law equation:
Exam Tip
The 'magnitude' of the e.m.f just means its size, rather than direction. This is often what is required in exam questions, so the minus sign in Lenz's law is often not needed in calculations.
However, you may be expected to explain the significance of the minus sign. Be prepared to interpret it as an expression of Lenz's Law. You can find this is described on the next page.
转载自savemyexams
以上就是关于【IB DP Physics: HL复习笔记11.1.3 Faraday’s Law】的解答,如需了解学校/赛事/课程动态,可至翰林教育官网获取更多信息。
往期文章阅读推荐:
别被“减负”骗了!IB改革真相:一场针对传统学霸的精准淘汰!

© 2026. All Rights Reserved. 沪ICP备2023009024号-1