
The resultant force F at an angle θ to the horizontal

The resultant force F can be split into its horizontal and vertical components

The weight vector of an object on an inclined plane can be split into its components parallel and perpendicular to the slope
A helicopter provides a lift of 250 kN when the blades are tilted at 15º from the vertical.
Calculate the horizontal and vertical components of the lift force.
Step 1: Draw a vector triangle of the resolved forces

Step 2: Calculate the vertical component of the lift force
Vertical = 250 × cos(15) = 242 kN
Step 3: Calculate the horizontal component of the lift force
Horizontal = 250 × sin(15) = 64.7 kN
If you're unsure as to which component of the force is cos θ or sin θ, just remember that the cos θ is always the adjacent side of the right-angled triangle AKA, making a 'cos sandwich'

Three forces on an object in equilibrium form a closed vector triangle
A weight hangs in equilibrium from a cable at point X. The tensions in the cables are T1 and T2 as shown.
Which diagram correctly represents the forces acting at point X?

The diagrams in exam questions about this topic could ask you to draw to scale, so make sure you have a ruler handy!
转载自savemyexams
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