The work function + the maximum kinetic energy of the photoelectron
E = hf = Φ + ½ mv2max
y = mx + c
Ek(max) = hf - Φ

The graph below shows how the maximum kinetic energy Ek of electrons emitted from the surface of sodium metal varies with the frequency f of the incident radiation.
Calculate the work function of sodium in eV.
Step 1: Write out the photoelectric equation and rearrange to fit the equation of a
straight line
E = hf = Φ + ½ mv2max → Ek(max) = hf - Φ
y = mx + c
Step 2: Identify the threshold frequency from the x-axis of the graph
When Ek = 0, f = f0
Therefore, the threshold frequency is f0 = 4 × 1014 Hz
Step 3: Calculate the work function
From the graph at f0, ½ mvmax2 = 0
Φ = hf0 = (6.63 × 10-34) × (4 × 1014) = 2.652 × 10-19 J
Step 4: Convert the work function into eV
1 eV = 1.6 × 10-19 J J → eV: divide by 1.6 × 10-19

When using the photoelectric effect equation, hf, Φ and Ek(max) must all have the same units (joules). Therefore make sure to convert any values given in eV into Joules (× (1.6 × 10-19))

Graphs showing the variation of electron KE and photocurrent with the frequency of the incident light
转载自savemyexams
以上就是关于【AQA A Level Physics复习笔记2.4.3 The Photoelectric Equation】的解答,如需了解学校/赛事/课程动态,可至翰林教育官网获取更多信息。
往期文章阅读推荐:
全网破防!ALevel CIE数学M1疑似错题?经济P2难度飙升?5月6日大考考情分析必看!
A-Level CIE就大规模泄题发布最严处罚!哪些考生必须重考?你的成绩怎么办?

© 2026. All Rights Reserved. 沪ICP备2023009024号-1