
Example of a working out what is conserved in Kaon decay. This decay must be through the weak interaction since S is not conserved
The lambda nought particle Λ0 is made up from the quarks uds.Show, in terms of the conservation of charge, strangeness, baryon number and lepton number whether the following interaction is permitted
Step 1: Determine conservation of charge
0 = –1 + 1 + 0
Charge is conserved
Step 2: Determine conservation of strangeness
Λ0 has an s quark, so must have a strangeness of –1
–1 = 0 + 0 + 0
Strangeness is not conserved
Step 3: Determine conservation of baryon number
Λ0 is a baryon since it has 3 quarks, so must have a baryon number of +1
+1 = 0 + 0 + 0
Baryon number is not conserved
Step 4: Determine conservation of lepton number
Λ0 is a baryon, so must have a lepton number of 0
0 = 0 + (–1) + 1
Lepton number is conserved
Step 5: Conclusion
Since the baryon number is not conserved, this interaction is not permitted
The equation for β– decay is
Using the quark model of beta decay, prove that the charge is conserved in this equation.

Note:
转载自savemyexams
以上就是关于【AQA A Level Physics复习笔记2.3.5 Application of Conservation Laws】的解答,如需了解学校/赛事/课程动态,可至翰林教育官网获取更多信息。
往期文章阅读推荐:
全网破防!ALevel CIE数学M1疑似错题?经济P2难度飙升?5月6日大考考情分析必看!
A-Level CIE就大规模泄题发布最严处罚!哪些考生必须重考?你的成绩怎么办?

© 2026. All Rights Reserved. 沪ICP备2023009024号-1