Edexcel IGCSE Maths 复习笔记 4.10.1 Sine & Cosine Rules, Area of a Triangle - Basics


sin 90° =1 – so if one of the angles is 90°, this becomes ‘SOH’ from SOHCAHTOA
a2 = b2 + c2 – 2bc cos A
cos 90° = 0 so if A = 90°, this becomes Pythagoras’ Theorem
Area = ½ ab sin C

b2 = a2 + c2 - 2ac cos B
c2 = a2 + b2 - 2ab cos C
Note that it’s always the angle between the two sides in the final term

Note that it’s always the angle between the two sides on the right-hand side –you can always just relabel the sides and angles of your triangle, though, instead of worrying about alternate versions of the last two formulas




转载自savemyexam
以上就是关于【Edexcel IGCSE Maths 复习笔记 4.10.1 Sine & Cosine Rules, Area of a Triangle - Basics】的解答,如需了解学校/赛事/课程动态,可至翰林教育官网获取更多信息。
往期文章阅读推荐:
深耕九载!30+国际竞赛/课程讲义,硕博100%团队操刀,助力爬藤冲G5!

© 2026. All Rights Reserved. 沪ICP备2023009024号-1