percentage error = (uncertainty value ÷ your measurement) x 100
In an enzyme rate reaction involving the breakdown of hydrogen peroxide by catalase, 50 cm3 of oxygen was produced, with an uncertainty value of 0.05 cm3. Calculate the percentage error of this measurement.
Percentage error = (uncertainty value ÷ your measurement) x 100
Percentage error = (0.05 ÷ 50) x 100
Percentage error = 0.001 x 100
Percentage error = 0.1%
In an enzyme rate experiment involving the breakdown of hydrogen peroxide by catalase, a student recorded that 10 cm3 of oxygen was produced in 5.245 seconds. The student measured this using a stopwatch that counted in milliseconds. Calculate the percentage error of the stopwatch measurements.
Step 1: Calculate the uncertainty value
The stopwatch can measure to the nearest millisecond (0.001 second)
This means the actual time taken could be up to 0.0005 seconds shorter or longer than this
This means stopwatch measurements have an uncertainty value of ± 0.0005 s
Step 2: Calculate the percentage error of the student’s measurement of 5.245 seconds
Percentage error = (uncertainty value ÷ your measurement) x 100
Percentage error = (0.0005 ÷ 5.245) x 100
Percentage error = 0.000095 x 100
Percentage error = 0.0095% or 0.01%
转载自savemyexams
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