Na(s) + ½Cl2 (g) → NaCl (s) ΔHfꝋ = -411 kJ mol -1
Na (g) → Na+ (g) + e– ΔHieꝋ = +500 kJ mol-1
Na (s) → Na (g) ΔHatꝋ = +108 kJ mol -1
Writing equations for the standard enthalpy change of atomisationWrite down the equations for the standard enthalpy change of atomisation (ΔHatꝋ) for:
(i) Potassium
(ii) Mercury
Answer
Answer 1: Potassium in its elemental form is a solid, therefore the standard enthalpy change of atomisation is the energy required to form 1 mole of K(g) from K(s)
K(s) → K(g)
Answer 2: Mercury in its elemental form is a liquid, so the standard enthalpy change of atomisation of mercury is the energy required to form 1 mole of Hg(g) from Hg(l)
Hg(l) → Hg(g)
Cl2 (g) → 2Cl (g) E(Cl-Cl) = +242 kJ mol -1
½Cl2 (g) → Cl (g) ΔHatꝋ = +121 kJ mol -1
Na+(g) + Cl-(g) → NaCl (s) ΔHlattꝋ = -776 kJ mol -1
Writing equations for lattice energyWrite down the equations which represent the lattice energy of:
(i) Magnesium oxide
(ii) Lithium chloride
Answer
Answer 1: Mg2+ (g) + O2- (g) → MgO (s)
Answer 2: Li+ (g) + Cl- (g) → LiCl (s)
Cl (g)+ e– → Cl- (g) ΔHeaꝋ = -364 kJ mol-1
O– (g) + e– → O2- (g) ΔHeaꝋ = +844 kJ mol-1
Make sure the correct state symbols are stated when writing these equations – it is crucial that you use these correctly throughout this entire topic.
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