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Part A选择题部分:
Part B简答题部分
Solution to Problem 1:
a) Free-body diagrams:

mg represents the weight of an object. N is the reaction force exerted by the ground on the cart, and N1 is the reaction force between m1 and M . T is the tension in the string.b) The three equations of motion are
T = m1 a1 (1) m2 g − T = m2 a2 (2)
T = MA (3)
where a1, a2 and A are the accelerations of m1, m2 and M, respectively. The vertical forces on M cancel each other, and so do those acting on m1. M accelerates (to the left) because the string exerts a force T to the left on the pulley.c) Imagine yourself accelerating with respect to the ground, so that M is stationary with respect to you. Then the acceleration of m1 with respect to you (and therefore with respect to M) is a2 to the right, since the length of the string does not change. With respect to the ground, we must have
a1 = a2 − A (4)
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