The binding energy of a nucleus divided by the number of nucleons in the nucleus

By plotting a graph of binding energy per nucleon against nucleon number, the stability of elements can be inferred
Determine the binding energy per nucleon of Iron-56 (
) in MeV
Mass of a neutron = 1.675 × 10−27 kg
Mass of a proton = 1.673 × 10−27 kg
Mass of a
nucleus = 9.228 × 10−26 kg
Step 1: Calculate the mass defect
Number of protons, Z = 26
Number of neutrons, A – Z = 56 – 26 = 30
Mass defect, Δm = Zmp + (A – Z)mn – mtotal
Δm = (26 × 1.673 × 10-27) + (30 × 1.675 × 10-27) – (9.288 × 10-26)
Δm = 8.680 × 10-28 kg
Step 2: Calculate the binding energy of the nucleus
Binding energy, ΔE = Δmc2
E = (8.680 × 10-28) × (3.00 × 108)2 = 7.812 × 10-11 J
Step 3: Calculate the binding energy per nucleon
Binding energy per nucleon = ![]()
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Step 4: Convert to MeV
J → eV: divide by 1.6 × 10-19
eV → MeV: divide by 106
binding energy per nucleon = ![]()
Checklist on what to include (and what not to include) in an exam question asking you to draw a graph of binding energy per nucleon against nucleon number:
转载自savemyexams
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