Moment (N m) = Force (N) × perpendicular distance from the pivot (m)

The force might not always be perpendicular to the distance
A uniform metre rule is pivoted at the 50 cm mark.
A 0.5 kg weight is suspended at the 80 cm mark, causing the rule to rotate about the pivot.
Assuming the weight of the rule is negligible, what is the turning moment about the pivot?


If not already given, drawing all the forces on an object in the diagram will help you see which ones are perpendicular to the distance from the pivot. Not all the forces will provide a turning effect and it is not unusual for a question to provide more forces than required to throw you off!
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