Fe(III) = iron with ox. no. +3

Answer





Cu + H2O → CuO + H2
(Cu has gained an oxygen and is oxidised)
2NH3 + 3Br2 → N2 + 6HBr
(N has lost a hydrogen and is oxidised)
Cu2+ → Mg → Mg2+ + Cu
(Mg has lost two electrons and is oxidised)
Cu2+ + Mg → Mg2+ + Cu
(change in ox. no. of Mg is +2 thus Mg is oxidised)
Cu+ H2O → 2CuO + H2
(O has been reduced)
2NH3+ 3Br2 → N2 + 6HBr
(Br has been reduced)
Cu2+ + Mg → Mg2+ + Cu
(Cu has been reduced)
Cu2+ + Mg → Mg2+ + Cu
(change in ox. no. of Cu is -2 thus Cu is reduced)

Use the acronym "Oil Rig" to help you remember the definitions of oxidation and reduction
Cu2++ Mg → Mg2+ + Cu
(Cu has been reduced and Mg has been oxidised)

Answer
Answer 1:
Oxidised: Cl- as the ox. no. has increased by 1Reduced: Na+ as the ox. no. has decreased by 1
Answer 2:
Oxidised: Mg as the ox. no. has increased by 2
Reduced: Fe2+ as the ox. no. has decreased by 2
Answer 3:
Oxidised: C as it has gained oxygenReduced: Ag as it has lost oxygen
Example of a disproportion reaction in which the same species (chlorine in this case) has been both oxidised and reduced

Answer





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