
One mole of water is formed from hydrogen and oxygen releasing 286 kJ
H2 (g) + ½O2 (g) → H2O (l) ΔHrꝊ= -286 kJ mol-1
Calculate ΔHr for the reaction below:2H2 (g) + O2 (g) → H2O (l)
Answer:
ΔHr = 2 mol x (-286 kJ mol-1)
= - 572 kJ
Calculate ΔHr for the reaction below
4Fe (s) +O2 (g) → 2Fe2O3 (s)
given that ΔHf Ꝋ [Fe2O3 (s)] = - 824 kJ mol-1
Answer:
ΔHf = 2 mol x ( -824 kJ mol-1)
= - 1648 kJ
Identify each of the following as ΔHrꝊ, ΔHfꝊ, ΔHcꝊ or ΔHꝊneut
Answer:
Answer 1: ΔHrꝊ
Answer 2: ΔHfꝊ as one mole of CO2 is formed from its elements in standard state and ΔHcꝊ as one mole of carbon is burnt in oxygen
Answer 3: ΔHneutꝊ as one mole of water is formed from the reaction of an acid and alkali
You need to learn well the Standard Enthalpy change definitions as they are frequently tested in exam papers
转载自savemyexams
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