If an object is balanced, the total clockwise moment about a pivot equals the total anticlockwise moment about that pivot

Moments on a balanced beam
Total clockwise moments = Total anticlockwise moments
F2 × d2 = (F1 × d1) + (F3 × d3)
A parent and child are at opposite ends of a playground see-saw. The parent weighs 690 N and the child weighs 140 N. The adult sits 0.3 m from the pivot.
Calculate the distance the child must sit from the pivot for the see-saw to be balanced.
Step 1: List the know quantities
Step 2: Write down the relevant equation
Moment = force × distance from pivot
Total clockwise moments = Total anticlockwise moments
Step 3: Calculate the total clockwise moments
Momentchild = Fchild × dchild = 140 × dchild
Step 4: Calculate the total anticlockwise moments
Momentadult = Fadult × dadult = 690 × 0.3 = 207 Nm
Step 5: Substitute into the principle of moments equation
140 × dchild = 207
Step 6: Rearrange for the distance of the child from the pivot
dchild = 207 ÷ 140 = 1.48 m
Make sure that all the distances are in the same units and you’re considering the correct forces as clockwise or anticlockwise, as seen in the diagram below
Clockwise is defined as the direction the hands of a clock move (and anticlockwise as the opposite)
F1 and F2 upwards balance the weight of the beam downwards

F1 decreases F2 increases keep the beam balanced

When F2 is removed the beam will rotate by the clockwise moment
转载自savemyexam
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