AQA A Level Chemistry复习笔记5.2.5 Finding Activation Energy
Finding Activation Energy
Finding the Activation Energy
- Very often, the Arrhenius Equation is used to calculate the activation energy of a reaction
- Either a question will give sufficient information for the Arrhenius equation to be used, or a graph can be plotted and the calculation done from the plot
Using the equation:
- Remember, it is usually easier to use the version of the Arrhenius equation after natural logs of each side have been taken
Worked Example
Calculate the activation energy of a reaction which takes place at 400 K, where the rate constant of the reaction is 6.25 x 10-4 s-1.
A = 4.6 x 1013 and R = 8.31 J K-1 mol-1.
Answer
Using an Arrhenius plot:
- A graph of ln k against 1/T can be plotted, and then used to calculate Ea
- This gives a line which follows the form y = mx + c
The graph of ln k against 1/T is a straight line with gradient -Ea/R
- From the graph, the equation in the form of y = mx + c is as follows:
Worked Example
Complete the following table, plot a graph of ln k against 1/T and use this to calculate the activation energy, Ea, and the Arrhenius Constant, A, of the reaction.
Answer
Calculate the activation energy, Ea, and the Arrhenius Constant, A, of the reaction:
Exam Tip
You are not required to learn these equations. However, you do need to be able to rearrange them, and knowing them is helpful in understanding the effects of temperature on the rate constant.
转载自savemyexams
以上就是关于【AQA A Level Chemistry复习笔记5.2.5 Finding Activation Energy】的解答，如需了解学校/赛事/课程动态，可至翰林教育官网获取更多信息。
往期文章阅读推荐：
生物竞赛金牌教练的实战书单！生物学/生物化学/病理学...电子版免费领！
翰林AMC8视频课重磅上线！
国际竞赛真题资源免费领取
