USACO 2016 US Open Contest, Silver Problem 2. Diamond Collector

原题下载：

USACO2016-OPEN-S2

答案：
import java.io.*;
import java.util.*;
public class diamondS {
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new FileReader("diamond.in"));
PrintWriter pw = new PrintWriter(new BufferedWriter(new FileWriter("diamond.out")));
StringTokenizer st = new StringTokenizer(br.readLine());
int n = Integer.parseInt(st.nextToken());
int k = Integer.parseInt(st.nextToken());
int[] list = new int[n];
for(int i = 0; i < n; i++) {
list[i] = Integer.parseInt(br.readLine());
}
Arrays.sort(list);
// leftmostIndex[i] stores the index of the smallest diamond that can be included given that
// the largest diamond in the case has size list[i].
int[] leftmostIndex = getLeftmost(list, k);
// leftSize[i] stores the maximum number of diamonds given that all diamonds have size at most list[i].
int[] leftSize = new int[n];
for(int i = 0; i < n; i++) { leftSize[i] = i - leftmostIndex[i] + 1; if(i > 0) {
leftSize[i] = Math.max(leftSize[i], leftSize[i-1]);
}
}
// rightmostIndex[i] stores the index of the smallest diamond that can be included given that
// the smallest diamond in the case has size list[i].
int[] rightmostIndex = getRightmost(list, k);
// leftSize[i] stores the maximum number of diamonds given that all diamonds have size at least list[i].
int[] rightSize = new int[n];
for(int i = n-1; i >= 0; i--) {
rightSize[i] = rightmostIndex[i] - i + 1;
if(i < n-1) {
rightSize[i] = Math.max(rightSize[i], rightSize[i+1]);
}
}
int ret = 0;
for(int i = 0; i < n-1; i++) { ret = Math.max(ret, leftSize[i] + rightSize[i+1]); } pw.println(ret); pw.close(); } public static int[] getRightmost(int[] list, int k) { int[] ret = new int[list.length]; int j = list.length-1; for(int i = list.length-1; i >= 0; i--) {
while(j >= 0 && list[j] - list[i] > k) {
j--;
}
ret[i] = j;
}
return ret;
}

public static int[] getLeftmost(int[] list, int k) {
int[] ret = new int[list.length];
int j = 0;
for(int i = 0; i < list.length; i++) {
while(j < list.length && list[i] - list[j] > k) {
j++;
}
ret[i] = j;
}
return ret;
}

}

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