
As waves pass through the aperture, they spread out

The size of the gap (compared to the wavelength) affects how much the waves spread out

When a wave goes past the edge of a barrier, the waves can curve around it
An electric guitar student is practising in his room. He has not completely shut the door of his room, and there is a gap of about 10 cm between the door and the door frame.
Determine the frequencies of sound that are best diffracted through the gap.
The speed of sound can be taken to be 340 m s–1
Step 1: Optimal diffraction happens when the wavelength of the waves is comparable to (or larger than) the size of the gap
λ = 10 cm = 0.1 m
Step 2: Write down the wave equation
c = fλ
Step 3: Rearrange the above equation for the frequency f
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Step 4: Substitute the numbers into the above equation
![]()
f = 3400 Hz
The frequencies of sound that are best diffracted through the gap are:
f ≤ 3400 Hz
When a wave is travelling through the air, which scenario best demonstrates diffraction?
A. UV radiation through a gate post
B. Sound waves passing a diffraction grating
C. Radio waves passing between human hair
D. X-rays passing through atoms in a crystalline solid
ANSWER: D
Consider option A:
Consider option B:
Consider option C:
Consider option D:
When drawing diffracted waves, take care to keep the wavelength (the distance between each wavefront) constant.
转载自saveyexams
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