The potential difference across the capacitor increases as the amount of charge increases

As the charge on the negative plate builds up, more work needs to be done to add more charge
Area = 0.5 × base × height

The electric energy stored in the capacitor is the area under the potential-charge graph



The variation of the potential V of a charged isolated metal sphere with surface charge Q is shown on the graph below.
Using the graph, determine the electric potential energy stored on the sphere when charged to a potential of 100 kV.
Step 1: Determine the charge on the sphere at the potential of 100 kV

Step 2: Calculate the electric potential energy stored
Area = 0.5 × base × height
Area = 0.5 × 1.8 μC × 100 kV
Energy E = 0.5 × (1.8 × 10-6) × (100 × 103) = 0.09 J
Calculate the change in the energy stored in a capacitor of capacitance 1500 μF when the potential difference across the capacitor changes from 10 V to 30 V.
Step 1: Write down the equation for energy stored, in terms of C and V and list the known values

Capacitance, C = 1500μF
Final p.d, V2 = 30 V
Initial p.d V1 =10 V
Step 2: The change in energy stored in proportional to the change in p.d

Step 3: Substitute in the values
All 3 equations for the energy stored will be given on your data sheet. To figure out which to use, check what variables (C, Q or V) have already been given in the question.
转载自savemyexams
以上就是关于【AQA A Level Physics复习笔记7.6.3 Energy Stored by a Capacitor】的解答,如需了解学校/赛事/课程动态,可至翰林教育官网获取更多信息。
往期文章阅读推荐:
MIT官方发布【2026年夏季推荐阅读书单】!横跨科学/人文/经济...

© 2026. All Rights Reserved. 沪ICP备2023009024号-1